Final answer:
The translation and reflection of Triangle XYZ to form Triangle X'Y'Z' results in the triangle being moved up and inverted across the x-axis, but does not inherently make its sides parallel to or perpendicular with the x-axis unless they already were.
Step-by-step explanation:
When Triangle XYZ is translated 2 units up and reflected across the x-axis to form Triangle X'Y'Z', several changes occur. Firstly, the translation does not alter the shape or orientation of the triangle but simply moves it two units higher in the coordinate plane. Secondly, the reflection across the x-axis inverts the triangle over the x-axis, meaning that every point on Triangle XYZ that was at a certain height above the x-axis will now be the same distance below it, and vice versa.
In terms of the options provided, neither a) that all three are parallel to each other and are along the x-axis, nor b) that all three are mutually perpendicular to each other, fully captures the result of the transformations applied to Triangle XYZ. Reflection and translation maintain parallelism and perpendicularity where they already existed, they do not create these characteristics where they did not.