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A car of mass 500 kg increases its velocity from 40 m/s to v m/s in 10 seconds. Find the acceleration, distance travelled, and amount of force applied.

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Final answer:

The acceleration is (v - 40) / 10, the distance travelled is 400 + 1/2 * (v - 40) * 100, and the force applied is 500 * ((v - 40) / 10).

Step-by-step explanation:

To find the acceleration, we can use the equation:

a = (v - u) / t

Where:

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

Plugging in the given values, we have:

a = (v - u) / t = (v - 40) / 10

To find the distance travelled, we can use the equation:

s = ut + 1/2at^2

Where:

  • s is the distance
  • u is the initial velocity
  • t is the time
  • a is the acceleration

Plugging in the given values, we have:

s = ut + 1/2at^2 = 40*10 + 1/2 * (v - 40) * 10^2

To find the amount of force applied, we can use Newton's second law:

F = ma

Where:

  • F is the force
  • m is the mass
  • a is the acceleration

Plugging in the given values, we have:

F = ma = 500 * ((v - 40) / 10)

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