Answer:
- J'(3, 6), K'(1.5, 1.5), L'(6, 0)
Explanation:
△ JKL is dilated by 3/2
This transformation will result in the coordinates:
Apply the rule:
- J(2, 4) → J'(3/2*2 = 3, 3/2*4= 6) = (3, 6)
- K(1, 1) → K'(3/2*1 = 1.5, 3/2*1 = 1.5) = (1.5, 1.5)
- L(4, 0) → L'(3/2*4 = 6, 3/2*0 = 0) = (6, 0)