Question

When 50.00 ml of an AgNO₃ solution is treated with excess dilute HCl, form 0.9876 g of AgCl. Calculate the molar concentration of the AgNO₃ solution?

Answer 1

To determine the molar concentration of the AgNO3 solution, calculate the moles of AgCl produced, which is equal to the moles of AgNO3, and then divide by the volume of the AgNO3 solution in liters. The result is a molar concentration of 0.1378 M.

Step-by-step explanation:

Calculating the Molar Concentration of AgNO3 Solution

Starting with the given mass of AgCl that forms (0.9876 g), we use the molar mass of AgCl (143.32 g/mol) to find the moles of AgCl and thus AgNO3 since they react in a 1:1 ratio. From there, the molar concentration of the AgNO3 solution can be determined by using the volume of the solution (50.00 mL or 0.05000 L).

Step-by-step solution:

1. Calculate moles of AgCl:
   (0.9876 g AgCl) × (1 mol AgCl / 143.32 g AgCl) = 0.00689 moles of AgCl.
2. AgNO3 reacts with HCl in a 1:1 mole ratio to form AgCl, so moles of AgNO3 = moles of AgCl = 0.00689 moles.
3. Calculate molarity (M) of AgNO3 solution:
   Molarity = moles of solute / liters of solution = 0.00689 moles / 0.05000 L = 0.1378 M.

The molar concentration of the AgNO3 solution is therefore 0.1378 M.