Final answer:
The question pertains to stoichiometry and the law of conservation of mass, but specific details to calculate the mass of calcium carbonate needed for 598 grams of calcium carbide are not provided.
Step-by-step explanation:
The question concerns the stoichiometry involved in converting from one chemical compound to another, specifically from calcium carbonate to calcium carbide. To answer how many grams of calcium carbonate are needed to form 598 grams of calcium carbide, we must use the stoichiometry of the involved chemical reactions. According to the given examples, heating 10 grams of calcium carbonate (CaCO₃) produces 4.4 g of carbon dioxide (CO₂) and 5.6 g of calcium oxide (CaO).
Since the mass of the reactants equals the mass of the products, this is in agreement with the law of conservation of mass. However, we have no direct conversion from calcium carbonate to calcium carbide in the provided examples. Usually, one would use the respective molar masses and the balanced chemical equations to calculate this, but without the pertinent reaction or molar masses, we cannot calculate the exact mass required of calcium carbonate.