Final answer:
The pH of the solution is 8.
Step-by-step explanation:
The pH of a solution can be calculated using the formula:
pH = -log[H+]
For the given solution containing 6.0 g of Ba(OH)₂ in a 525-mL aqueous solution, we need to calculate the concentration of [H+].
To do this, we first need to calculate the moles of Ba(OH)₂:
Moles = mass / molar mass = 6.0 g / (137.33 g/mol + 2(16.00 g/mol + 1.01 g/mol)) = 0.0249 mol
Next, we need to calculate the molarity (M) of the solution:
Molarity = moles / volume = 0.0249 mol / 0.525 L = 0.0474 M
Now, we can calculate the concentration of [H+] using the formula:
[H+] = 10^(-pH)
pH = -log[H+] = -log(10^(-8)) = -(-8) = 8
Therefore, the pH of the solution is 8.