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A sum of money was to be shared among three friends, Albert, Bruce, and Christine, in the ratio 3^:7^:10^. If Christine received $495 more than Bruce, find the sum of money shared.

User Lee Dykes
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Final answer:

The sum of money shared among three friends in the ratio 3:7:10, with Christine receiving $495 more than Bruce, was $3300.

Step-by-step explanation:

The question involves determining the total sum of money shared among three friends in a given ratio. To solve this, we are given that the money is shared among Albert, Bruce, and Christine in the ratio of 3:7:10. The additional information provided is that Christine received $495 more than Bruce. Assuming the parts of the ratio they received are 3x, 7x, and 10x respectively, and given that 10x - 7x = $495, we can solve for x and subsequently find the total sum shared.

Step 1: Write down the equation based on the information given about the money Christine received more than Bruce.

10x - 7x = $495

Step 2: Solve for x.

3x = $495

x = $495 / 3

x = $165

Step 3: Find the total sum of money by adding the shares of Albert, Bruce, and Christine together using the solved value of x.

Total Sum = 3x + 7x + 10x

Total Sum = 20x

Total Sum = 20($165)

Total Sum = $3300

Therefore, the sum of money shared among the three friends was $3300.

User Rubans
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