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Complete combustion of 5.40 g of a hydrocarbon produced 17.4 g of CO₂ and 5.92 g of H₂O. What is the empirical formula for the hydrocarbon? Insert subscripts as necessary.

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Final answer:

The empirical formula of the hydrocarbon is CH₂.

Step-by-step explanation:

The empirical formula can be determined by using the law of conservation of mass. Given that 5.40 g of the hydrocarbon produced 17.4 g of CO₂ and 5.92 g of H₂O, we can calculate the moles of each element involved. First, determine the moles of carbon in CO₂:

17.4 g CO₂ x (1 mol CO₂/44.01 g CO₂) = 0.395 mol CO₂

Next, determine the moles of carbon in the hydrocarbon:

0.395 mol CO₂ x (1 mol C/1 mol CO₂) = 0.395 mol C

Then, determine the moles of hydrogen in H₂O:

5.92 g H₂O x (1 mol H₂O/18.02 g H₂O) = 0.328 mol H₂O

Finally, determine the moles of hydrogen in the hydrocarbon:

0.328 mol H₂O x (2 mol H/1 mol H₂O) = 0.656 mol H

The empirical formula of the hydrocarbon is C₀.₃₉₅H₀.₆₅₆, which can be simplified to CH₂

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