196k views
5 votes
What will the final temperature be when 200^3 of hot water (95°C) are poured into a glass (_=840 /(⋅°)) cup with a mass of 150g initially at 15°C.

1 Answer

7 votes

Final answer:

To calculate the final temperature when hot water is poured into a glass cup, you can use the principle of conservation of energy. The final temperature when 200g of hot water at 95°C is poured into a cup with a mass of 150g initially at 15°C is approximately -40.48°C.

Step-by-step explanation:

To calculate the final temperature when hot water is poured into a glass cup, you can use the principle of conservation of energy, specifically the equation for heat transfer: Q = mcΔT. Q represents the heat transferred, m is the mass, c is the specific heat, and ΔT is the change in temperature. In this case, the initial temperature of the water is 95°C and the initial temperature of the cup is 15°C.

First, calculate the heat transferred from the hot water to the cup:

Q1 = mcΔT1

Q1 = (200g)(840 J/(g°C))(15°C - 95°C)

Q1 = -240,000 J

Next, calculate the heat transferred from the hot water to the cup:

Q2 = mcΔT2

Q2 = (150g)(840 J/(g°C))(15°C - t)

Q2 = 1260t - 189,000 J

Since the heat transferred from the hot water to the cup is equal to the heat transferred from the cup to the cold water, set Q1 equal to Q2:

-240,000 J = 1260t - 189,000 J

Solve for t:

t = (-240,000 J + 189,000 J) / 1260 J/°C

t = -51,000 J / 1260 J/°C

t ≈ -40.48°C

Therefore, the final temperature when 200g of hot water at 95°C is poured into a cup with a mass of 150g initially at 15°C is approximately -40.48°C.

User Richiban
by
7.4k points