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Solve for k in the equation (21x - 3)(2x + 5) = 8x² + kx.

User Pherris
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Final answer:

To solve for k in the equation (21x - 3)(2x + 5) = 8x² + kx, you must expand and simplify the left-hand side to get 42x² + 99x - 15, which, when compared to the right-hand side, shows that k equals 99.

Step-by-step explanation:

To solve for k in the equation (21x - 3)(2x + 5) = 8x² + kx, we must first expand the left-hand side of the equation. The expanded form of the left-hand side will be:

42x² + 105x - 6x - 15 = 8x² + kx

Combining like terms, we get:

42x² + 99x - 15 = 8x² + kx

To find the coefficient k, we need to compare the corresponding terms from both sides of the equation:

42x² = 8x²

99x = kx

Since the x² terms on both sides of the equation already match, we can focus on the x terms. Therefore, k equals 99, as the coefficient in front of x on the left-hand side of the equation is 99 when it's fully expanded and simplified.

User Otto Fajardo
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