Question

A ball is shot directly up in the air from a dog ball launcher. The upwards velocity of the ball, in meters per second, after t seconds is approximated by the following expression. 35 – 10t seconds after being .The upwards velocity will be strictly between 15 and 20 meters per second between thrown in the air.

Answer 1

The student's physics question involves finding the time when a launched ball's velocity is between 15 and 20 m/s using the expression 35 - 10t for its velocity.

Step-by-step explanation:

The student's question is about the upwards velocity of a ball after being shot directly up in the air from a dog ball launcher. The velocity is given by the expression 35 – 10t where t is the time in seconds after being launched. To find when the upward velocity will be strictly between 15 and 20 meters per second, you would set up inequalities 15 < 35 - 10t < 20 and solve for t. This is a kinematics problem that involves concepts of linear motion under the effect of gravity, typically covered in high school physics courses.