Final answer:
The volume of NH₃ produced can be calculated using the molar volume at STP and the balanced chemical equation N₂ + 3 H₂ → 2 NH₃. For every 3 moles of H₂, 2 moles of NH₃ are produced. Convert the moles of NH₃ back to volume to get the answer.
Step-by-step explanation:
The question is asking for the volume of NH₃ (ammonia) produced at Standard Temperature and Pressure (STP) when 25.0 liters of H₂ (hydrogen gas) is reacted with an excess of N₂ (nitrogen gas). To solve this, we use the balanced chemical equation:
N₂ + 3 H₂ → 2 NH₃
Under STP conditions, gases occupy 22.4 L per mole. Assuming we have 25.0 L of H₂, we first need to calculate how many moles of H₂ we have using the molar volume (25.0 L H₂ / 22.4 L/mol), and then apply the stoichiometry of the reaction. For every 3 moles of H₂, 2 moles of NH₃ are produced. Finally, we convert moles of NH₃ back to volume.