Final answer:
The deceleration of a car which comes to a stop after traveling 37 m from an initial velocity of 90 km/h is approximately 8.45 m/s² in the opposite direction of motion.
Step-by-step explanation:
To determine the acceleration of a car as it comes to a stop, we can use the kinematic equation for uniformly accelerated motion:
v 2 = u 2 + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement (distance traveled).
Since the car comes to a stop, v = 0. We need to convert the initial velocity from km/h to m/s: 90 km/h = 25 m/s. We know that s = 37 m.
Now, the equation becomes:
0 = (25)2 + 2a (37)
Solving for a gives us:
0 = 625 + 74a
a = -625 / 74
a ≈ -8.45 m/s2
The deceleration of the car is 8.45 m/s2 in the opposite direction to the motion of the car.