Final answer:
In a population of 200 people with 16 individuals having brown hair (B), the predicted frequencies are as follows:
(a) Approximately 184 individuals would be heterozygous,
(b) Approximately 1.28 individuals would be homozygous dominant,
(c) There would be no homozygous recessive individuals.
Step-by-step explanation:
In a population of 200 people, with 16 individuals having brown hair (B) and assuming brown hair is dominant to blond hair (b):
(a) The predicted frequency of heterozygous individuals can be calculated by subtracting the frequency of homozygous dominant individuals from the total population. In this case, the predicted frequency of heterozygous individuals would be 200 minus 16, which equals 184.
(b) The predicted frequency of homozygous dominant individuals can be calculated by multiplying the square of the proportion of individuals with brown hair. In this case, the proportion of individuals with brown hair is 16/200, which equals 0.08. Squaring this proportion gives us 0.0064, which can be multiplied by the total population (200) to obtain a predicted frequency of approximately 1.28.
(c) The predicted frequency of homozygous recessive individuals can be calculated by subtracting the frequency of homozygous dominant and heterozygous individuals from the total population. In this case, the predicted frequency of homozygous recessive individuals would be 200 minus 16 minus 184, which equals 0.