Final answer:
By setting up a system of equations and using elimination, we find that a van can carry 7 students and a bus can carry 42 students.
Step-by-step explanation:
To solve for the number of students that can fit in a van and a bus for High School A and B, we can set up a system of equations. Let v be the number of students that a van can carry and b be the number of students that a bus can carry.
- For High School A: 12v + 8b = 420
- For High School B: 6v + 13b = 588
We can solve this system using either substitution or elimination. Let's use elimination by multiplying the first equation by 6 and the second equation by 12 to make the coefficients of v the same:
- (6)(12v + 8b) = (6)(420)
- (12)(6v + 13b) = (12)(588)
This becomes:
- 72v + 48b = 2520
- 72v + 156b = 7056
Now we subtract the first new equation from the second:
- 72v + 156b - (72v + 48b) = 7056 - 2520
Which simplifies to:
Dividing by 108 gives us the number of students a bus can carry:
We can substitute b = 42 back into the first original equation:
Which simplifies to:
Subtracting 336 from 420 gives us:
Dividing by 12 gives us the number of students a van can carry:
So, a van can carry 7 students and a bus can carry 42 students.