Question

A A 40 militer volune of 1.8 molar Iron (ill) nitrate is mixed with 21.5 ml of 0.808 molar Iron (iii) nitrate solution. ) calculate the molar concentration of the final solution

(a) 0.808 M
(b) 1.8 M
(c) 1.452 M
(d) 2.312 M

Answer 1

The molar concentration of the final solution is approximately 1.452 M.

Step-by-step explanation:

To calculate the molar concentration of the final solution, we need to use the formula:

M1V1 = M2V2

Where M1 and V1 represent the initial molar concentration and volume, and M2 and V2 represent the final molar concentration and volume.

In this case, the initial volume (V1) is 40 mL, the initial molar concentration (M1) is 1.8 M, the added volume (V2) is 21.5 mL, and the added molar concentration (M2) is 0.808 M.

Plugging these values into the formula:

(1.8 M)(40 mL) = (M2)(61.5 mL)

Solving for M2:

M2 = (1.8 M)(40 mL) / (61.5 mL)

M2 ≈ 1.452 M

Therefore, the molar concentration of the final solution is approximately 1.452 M, which corresponds to option (c).