128k views
5 votes
Calculate C(4, 2) · C(9, 7) · C(11, 7), the product of combinations

(a) 6
(b) 36
(c) 330
(d) 71,280

User Baris Akar
by
7.8k points

1 Answer

5 votes

Final answer:

To calculate C(4, 2) · C(9, 7) · C(11, 7), we first find the values of each combination and then multiply them together. The product is 71,280.

Step-by-step explanation:

To calculate the product of combinations C(4, 2) · C(9, 7) · C(11, 7), we can first evaluate each individual combination, and then multiply them together.



C(4, 2) = 4! / (2!(4-2)!) = (4 · 3) / (2 · 1) = 6

C(9, 7) = 9! / (7!(9-7)!) = (9 · 8) / (2 · 1) = 36

C(11, 7) = 11! / (7!(11-7)!) = (11 · 10 · 9 · 8) / (4 · 3 · 2 · 1) = 330

Now, we can multiply these values together: 6 · 36 · 330 = 71,280.

User FeeFiFoFum
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories