Question

Due: Friday, December 10, 2021 at 11:59 pm Imagine you have two electricity circuits. One of the imagine you have two circuits. One of the circuits contain a resistor and a lightbulb and the other contains 2 resistors and a lightbulb, what happened to the lightbulb in the second circuit?

A) The lightbulb will be brighter than in the first circuit.
B) The lightbulb will be dimmer than in the first circuit.
C) The lightbulb will not light up at all.
D) The lightbulb will remain the same brightness as in the first circuit.

Answer 1

The lightbulb in the second circuit with two resistors will be dimmer than in the first circuit with one resistor due to the increased total resistance, which reduces current and therefore power dissipation.

Step-by-step explanation:

If we have two circuits, one with a resistor and a lightbulb, and another with two resistors and a lightbulb, the presence of an additional resistor in the second circuit increases the total resistance of the circuit. According to Ohm's law, the current through a circuit is inversely proportional to the total resistance. Therefore, the current in the second circuit will be lower than in the first circuit, since it has a higher total resistance.

Furthermore, the power dissipated by the lightbulb, which can be associated with brightness, is given by P = I^2R (where P is power, I is current, and R is resistance). With a lower current in the second circuit, the power dissipated by the lightbulb will also be lower. Consequently, the lightbulb in the second circuit will be dimmer than in the first circuit.

Thus, the correct answer is: B) The lightbulb will be dimmer than in the first circuit.