45.6k views
4 votes
"Using the following equation, find the zeros of the function:

f(x) = 2x^2 - 8x + 17
A) x = -1.53, 5.5
B) x = -.26, 3.26
C) x = 1.44, 7.56
D) There are no real solutions.

1 Answer

1 vote

Final answer:

To find the zeros of the function f(x) = 2x^2 - 8x + 17, use the quadratic formula and solve the equation 2x^2 - 8x + 17 = 0. The zeros of the function are the values of x that make the equation true.

Step-by-step explanation:

To find the zeros of the function f(x) = 2x^2 - 8x + 17, we need to solve the equation 2x^2 - 8x + 17 = 0. Using the quadratic formula, x = (-b ± √(b^2 - 4ac)) / 2a, where a = 2, b = -8, and c = 17. Plugging in these values, we get:

x = (-(-8) ± √((-8)^2 - 4(2)(17))) / (2(2))
x = (8 ± √(64 - 136)) / 4
x = (8 ± √(-72)) / 4

Since the expression inside the square root is negative, there are no real solutions. Therefore, the correct answer is D) There are no real solutions.

User Kayge
by
8.5k points

No related questions found