Question

What is the equation in point slope form of a line that passes through the point (-8, 2) and has a slope of 12?

Answer 1

Our answer is
`\boxed{\sf{y-2=12(x+8)}}`.

`\Large\texttt{Explanation}`

We are asked to find the equation for a line that :

• passes through (-8,2)
• has a slope of 12.

Since we know both the point and the slope, we'll use our point-slope formula:

`\multimap\qquad\boldsymbol{y-y_1=m(x-x_1)}`

where the point is
`\bf{(x_1,y_1)}` and the slope is
`\bf{m}`.

Plug in (-8,2) for the point & 12 for m -

`\multimap\qquad\boldsymbol{y-2=12(x-(-8)}`

`\multimap\qquad\boldsymbol{y-2=12(x+8)}` <= point-slope equation

Answer 2

You can look at solving steps in the attached image but the answer is y-2=12(x+8)