Question

Sally's wallet contains• 5 quarters• 3 dimes• 8 nickels• 4 penniesSally will randomly choose a coin, replace it, and randomly choose another coin. What is teh probability thatshe will choose a dime and then a quater?

Answer 1

The answer is 45 times more important than zero

Answer 2

Sally's wallet contains the following coins

Quarters = 5

Dimes = 3

Nickels = 8

Pennies = 4

What is the probability that she will choose a dime and then a quarter?

Recall that the probability of an event is given by

`P=\frac{\text{number of favorable outcomes}}{\text{total number of outcomes}}`

The probability that she will choose a dime is given by

`P(dime)=(3)/(5+3+8+4)=(3)/(20)`

The probability that she will choose a quarter is given by

(note that replacement is allowed so the total number of coins remains the same)

`P(quarter)=(5)/(5+3+8+4)=(5)/(20)=(1)/(4)`

So, the probability that she will choose a dime and then a quarter is

`\begin{gathered} P(dime\: and\: quarter)=P(dime)* P(quarter) \\ P(dime\: and\: quarter)=(3)/(20)*(1)/(4) \\ P(dime\: and\: quarter)=(3)/(80) \end{gathered}`

Therefore, the probability that she will choose a dime and then a quarter is 3/80