Question

What is the equation in slope-intercept form of the line that passes through the points (-8, -15) and (-6, 11)?

A) y = 8x - 71
B) y = 13x - 19
C) y = -13x + 19
D) y = -8x - 71

Answer 1

The equation in slope-intercept form of the line passing through the points (-8, -15) and (-6, 11) is y = 13x - 119.

Step-by-step explanation:

To find the equation in slope-intercept form, we need to determine the slope and the y-intercept of the line that passes through the points (-8, -15) and (-6, 11).

First, let's calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1).

Substitute the coordinates into the formula: m = (11 - (-15)) / (-6 - (-8)) = 26 / 2 = 13.

Next, we can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept.

Let's substitute the slope (m = 13) and one of the given points (for example, (-8, -15)) into the equation: -

15 = 13(-8) + b. Solve for b: b = -15 - 104 = -119.

Therefore, the equation in slope-intercept form is: y = 13x - 119.