Question

A 0.2 kg ball rotates at a constant speed of 3 m/s on the end of 1.2 m long string.

What is the centripetal force exerted on the object? Round the magnitude of your answer to the nearest tenths place.

Answer 1

The centripetal force exerted on the 0.2 kg ball rotating at the end of a 1.2 m string at 3 m/s is 0.9 N.

Step-by-step explanation:

To determine the centripetal force exerted on the ball, we can use the formula for centripetal force: Fc = m*v2/r, where m is the mass of the object, v is its constant speed, and r is the radius of the circular path. The mass of the ball (m) is given as 0.2 kg, the speed (v) is 3 m/s, and the length of the string, which is the radius of the circular motion (r), is 1.2 m.

Plugging these values into the equation, we get:

Fc = (0.2 kg) * (3 m/s)2 / (1.2 m) = 0.9 N

So, the centripetal force exerted on the object is 0.9 N, rounded to the nearest tenth.