Question

A 952 cm³ container of gas is exerting a pressure of 108 kPa while at a temperature of 48 °C. Calculate the pressure of this same amount of gas in a 1236 cm container at a temperature of 64 °C.

Answer 1

The final pressure of the gas when the volume is changed to 1236 cm³ at a temperature of 64 °C is 88.06 kPa, calculated using the combined gas law.

Step-by-step explanation:

The question involves the use of the combined gas law, which relates pressure, volume, and temperature of a gas. In the given problem, you have a 952 cm³ container of gas exerting a pressure of 108 kPa at 48 °C, and you need to calculate the pressure when the volume changes to 1236 cm³ at 64 °C.

Step-by-Step Solution

1. Convert the temperatures from °C to Kelvin by adding 273.15 to each. T1 = 48 °C = 321.15 K and T2 = 64 °C = 337.15 K.
2. Apply the combined gas law: P1 * V1 / T1 = P2 * V2 / T2.
3. Substitute the known values into the equation: 108 kPa * 952 cm³ / 321.15 K = P2 * 1236 cm³ / 337.15 K.
4. Solve for P2 (final pressure): P2 = (108 kPa * 952 cm³ / 321.15 K) * (337.15 K / 1236 cm³).
5. Calculate the final pressure: P2 = 88.06 kPa.

The final pressure of the gas when the volume is changed to 1236 cm³ and the temperature is 64 °C is 88.06 kPa.