Final answer:
The number of electrons transferred in the chemical equation Al + NH4ClO4 = Al2O3 + AlCl3 + N2 + H2O can be determined by balancing the half-reactions. The oxidation half-reaction involves aluminum, which is being oxidized: Al → Al3+ + 3e. The reduction half-reaction involves NH4ClO4, and can be balanced by multiplying it by 15: 15NH4ClO4 → 12H2O + 5N2 + 15H+ + 15e.
Step-by-step explanation:
The number of electrons transferred in the chemical equation Al + NH4ClO4 = Al2O3 + AlCl3 + N2 + H2O can be determined by balancing the half-reactions.
The oxidation half-reaction involves aluminum (Al), which is being oxidized:
Al → Al3+ + 3e
The reduction half-reaction involves NH4ClO4, and can be balanced by multiplying it by 15:
15NH4ClO4 → 12H2O + 5N2 + 15H+ + 15e
The number of electrons transferred in this reaction is 3.