Answer:
1 / We have the area of a rectangle ABCD = 8 x 16 = 128 ft²
2 / Find the area of an isosceles Δ DEF:
The base of the isosceles ΔDEF => DF = DC- FC = 16 -12 = 4 ft
So the area of Δ DEF = 1/2 (DF x EH) = 1/2 (4 x 6) = 12 ft²
3 / Area of the irregular shape = area ABCB + Area DEF = 128 + 12 = 140 ft²
Explanation: