Question

Point P’ (-3,2) is the image of point P (3,8) under a translation. What is the image of (0,-6) under the same translation?

A.(-3,-4)
B.(0,6)
C.(-6,-12)
D. (0,10)

Answer 1

To find the image of the point (0, -6) under the same translation, you need to determine the translation vector by using the given points (-3, 2) and (3, 8). Then, apply this vector to the point (0, -6) to find its image.

Step-by-step explanation:

To find the image of the point (0, -6) under the same translation, we need to determine the translation vector. The image of point P'(-3, 2) under the translation is obtained by moving point P(3, 8) by the same amount. The translation vector is given by: vector(P'P) = vector(P'P). Apply this vector to the point (0, -6) to find its image.

For point P, vector(P'P) = (-3 - 3, 2 - 8) = (-6, -6).

Therefore, the image of (0, -6) under the same translation is: (0, -6) + (-6, -6) = (-6, -12). Therefore, the image of (0, -6) under the translation is (-6, -12). Hence, the correct answer is C. (-6, -12).