Question

Fill in the value of a and b
(-ax² + 4)-(4x² + b) =-11x²+1

Answer 1

In the equation (-ax² + 4)-(4x² + b) = -11x²+1, by comparing coefficients, the value of a is determined to be 7 and the value of b is determined to be 3.

Step-by-step explanation:

To find the values of a and b in the equation (-ax² + 4)-(4x² + b) =-11x²+1, we need to compare the coefficients on both sides of the equation.

First, combine like terms on the left side of the equation:

• -ax² - 4x² + 4 - b = -11x² + 1

Next, group the x² terms together and the constant terms together:

• (-a - 4)x² + (4 - b) = -11x² + 1

By comparing coefficients, we find that:

• -a - 4 = -11
• 4 - b = 1

Solving the first equation for a gives us a = 7. Solving the second equation for b gives us b = 3.

Thus, the value of a is 7 and the value of b is 3.