Final answer:
To find the components of a vector, we can use trigonometry. For vector P of length 5 m directed at 150° counterclockwise from the x-axis, the x-component is -2.5 m and the y-component is 4.33 m. For vector Q of length 3.6 m directed at 120° clockwise from the +y-axis, the x-component is -1.96 m and the y-component is -1.8 m.
Step-by-step explanation:
To find the components of a vector, we can use trigonometry. Let's take a look at each vector separately:
a) P of length 5 m directed at 150° counterclockwise from the x-axis. To find the x-component, we use the equation Ax = A cos 0, so Ax = 5 m * cos(150°) = -2.5 m.
To find the y-component, we use the equation Ay = A sin 0, so Ay = 5 m * sin(150°) = 4.33 m.
b) Q of length 3.6 m directed at 120° clockwise from the +y-axis. To find the x-component, we use the equation Qx = Q sin 0, so Qx = 3.6 m * sin(120°) = -1.96 m. To find the y-component, we use the equation Qy = Q cos 0, so Qy = 3.6 m * cos(120°) = -1.8 m.