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The height of a golf ball hit into the air is modeled by the equation h=-16t^2+48t, where H represents the height, in feet, and he represents the number of seconds that have passed since the ball was hit. What is the height of the ball after two seconds?

User Osorio
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1 Answer

5 votes

Answer:

Height = 32 feet.

Explanation:

Substituting for t in the equation:

t = 2 so,

h = -16(2)^2 + 48(2)

= -64 + 96

= 32 feet.

User Meric Ozcan
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