Question

A crate is carried by a conveyor belt to a loading dock. The belt speed uniformly increases slightly, so that for 28.0 s the crate accelerates by 0.035 m/s². If the crate's initial speed is 0.76 m/s, what is its final speed?

Answer 1

Using the kinematic equation for acceleration, the final speed of the crate on the conveyor belt which accelerates uniformly for 28.0 seconds at 0.035 m/s² with an initial speed of 0.76 m/s, is calculated to be 1.74 m/s.

Step-by-step explanation:

To determine the final speed of a crate on a conveyor belt that accelerates uniformly, we can use the kinematic equation for acceleration: v = u + at, where v is the final velocity, u is the initial velocity, a is acceleration, and t is time.

In this case, the crate's initial speed (u) is 0.76 m/s, the acceleration (a) is 0.035 m/s², and the time (t) is 28.0 seconds. Plugging these values into the equation:

v = 0.76 m/s + (0.035 m/s² × 28.0 s)

v = 0.76 m/s + 0.98 m/s

v = 1.74 m/s

So the final speed of the crate is 1.74 m/s.