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A model airplane with a mass of 3.2 kg moves in a circular path with a radius of 12 m. If

the airplanes speed is 20 m/s, how large is the force that the control line exerts on the
plane to keep it moving in a circle?

1 Answer

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Final answer:

The centripetal force exerted by the control line on a model airplane with a mass of 3.2 kg, moving at a speed of 20 m/s in a circular path with a radius of 12 m, is 106.67 Newtons.

Step-by-step explanation:

The question asks for the centripetal force that the control line exerts on a model airplane to keep it moving in a circular path. Centripetal force can be calculated using the formula F = m × v^2 / r, where m is the mass of the object, v is the velocity, and r is the radius of the circular path. For a model airplane with a mass of 3.2 kg, a speed of 20 m/s, and a circular path radius of 12 m, the centripetal force is given by F = 3.2 kg × (20 m/s)^2 / 12 m.

Plugging the values into the formula, we get:

F = 3.2 kg × 400 m²/s² / 12 m

F = 1280 kg·m/s² / 12 m

F = 106.67 N

Therefore, the force that the control line exerts on the airplane to keep it moving in a circle is 106.67 Newtons.

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