Final answer:
The question seems to have a typo with the length of the rope missing. Assuming the rope is 14 feet long, two possible movements for Cecil are: 7 feet, then 4 feet, and finally 3 feet; or 10 feet, back 3 feet, then forward 4 feet and 3 feet, both adding up to 14 feet.
Step-by-step explanation:
It appears there is a typo in the original question as the length of the rope Cecil needs to cross is not provided. Nonetheless, the examples given for Cecil's movements on the rope are arithmetic expressions. We are asked to find at least two ways Cecil can move to reach the end of the rope using only lengths of given feet.
Let's assume the rope is 14 feet long as suggested by option A. Cecil could use a combination of steps that add up to the total length of the rope. For example:
- A. Cecil could first move 7 feet, then 4 feet, and finally 3 feet, totaling 14 feet (7 + 4 + 3 = 14 feet).
- D. Alternatively, Cecil could move 10 feet and then return 3 feet back, then move forward 4 feet and 3 feet again, to total 14 feet (10 - 3 + 4 + 3 = 14 feet).
The process described demonstrates the concept of simple addition and subtraction to reach a cumulative total distance, demonstrating the commutative property of addition where the order of the numbers being added does not change the sum, which is applicable to the motion of a tightrope walker as it would be in math.