Final answer:
Approximately 4936.96 liters of ammonia gas would be produced when 7.4 m³ of hydrogen gas is consumed in this reaction.
Step-by-step explanation:
The balanced chemical equation for the reaction between hydrogen gas and nitrogen gas to form ammonia gas is:
N₂(g) + 3H₂(g) -> 2NH₃(g)
From the balanced equation, we can see that 3 moles of hydrogen gas react to produce 2 moles of ammonia gas. To find the volume of ammonia gas produced, we need to use the given volume of hydrogen gas and the molar volume relationship.
One mole of any gas at standard temperature and pressure (STP) occupies a volume of 22.4 liters. Therefore, 7.4 m³ of hydrogen gas can be converted to volume at STP by multiplying by (1000 L / 1 m³) and then dividing by (22.4 L / 1 mol):
7.4 m³ * (1000 L / 1 m³) / (22.4 L / 1 mol) = 330.36 mol
Using the mole ratio from the balanced equation, we can calculate the volume of ammonia gas produced:
330.36 mol H₂ * (2 mol NH₃ / 3 mol H₂) * (22.4 L / 1 mol) = 4936.96 L
Therefore, approximately 4936.96 liters of ammonia gas would be produced when 7.4 m³ of hydrogen gas is consumed in this reaction.