Final answer:
The molarity of the solution prepared by dissolving 30.0 g of HCl in 150.0 mL of water is 5.48 M.The molarity of a solution prepared by dissolving 30.0 g of HCl in 150.0 mL of water is calculated as 5.49 M, which represents the number of moles of HCl per liter of solution.
Step-by-step explanation:
To find the molarity of the solution, we need to first calculate the number of moles of HCl. We can do this by using the formula:
moles = mass / molar mass
First, we need to calculate the molar mass of HCl, which is 36.46 g/mol. Then, substitute the values into the formula and calculate:
moles = 30.0 g / 36.46 g/mol = 0.822 mol
Next, we need to calculate the volume of the solution in liters. We convert 150.0 mL to liters by dividing by 1000:
volume = 150.0 mL / 1000 mL/L = 0.150 L
Finally, we can calculate the molarity using the formula:
molarity = moles / volume = 0.822 mol / 0.150 L = 5.48 M