Final answer:
In the reaction Zn + Cu₂+ → Zn₂+ + Cu, zinc is oxidized and copper ions are reduced.
Step-by-step explanation:
From the information given in the problem:
2+
anode (oxidation): Zn(s) → Zn²+ (aq) + 2e¯
cathode (reduction): Cu²+ (aq) +2 e¯ → Cu(s) overall: Zn(s) + Cu²+ (aq) → Zn²+ (aq) + Cu(s)