Question

A 6.57 kg ball rolls across the street at a rate of 7 m/s. What is the KE of 2. The ball before it hits the curb?

a)30 J
b)225.35 J
c)160.97 J​

Answer 1

The kinetic energy of a 6.57 kg ball rolling at 7 m/s is 160.97 J.

Step-by-step explanation:

The kinetic energy (KE) of the 6.57 kg ball rolling across the street at 7 m/s is calculated using the kinetic energy formula KE = 0.5 × mass × velocity2. Plugging in the values, we have KE = 0.5 × 6.57 kg × (7 m/s)2, which equals 160.97 J. Therefore, the kinetic energy of the ball before it hits the curb is 160.97 J.