51.8k views
0 votes
A sample mean, sample size, and sample standard deviation are provided below. Use the one-mean t-test to perform the required hypothesis test at the 1% significance level.

x = 22, s = 6, n=24, H0:u=21

User Jhunovis
by
8.3k points

1 Answer

3 votes

Final answer:

To perform the hypothesis test at the 1% significance level with the given sample data and null hypothesis, a one-mean t-test using the Student's t-distribution is appropriate. You calculate the test statistic with the given formula and compare it against the critical t value. Depending on the result, you either reject or fail to reject the null hypothesis.

Step-by-step explanation:

To perform a hypothesis test at the 1% significance level for the given sample data (sample mean: x = 22, sample standard deviation: s = 6, sample size: n = 24), and the null hypothesis (H0: μ = 21), you would use a one-mean t-test. Since we do not have the population standard deviation, the Student's t-distribution is appropriate.

First, we check if the underlying population is assumed to be normal, which is a requirement for the t-test. The sample size also needs to be considered, and since the sample size is less than 30, and there is no indication that the population is not normal, the t-distribution is suitable. To calculate the test statistic (t), we use the formula:

t = (x - μ) / (s/ √ n)

Using our data, we would calculate this as t = (22 - 21) / (6 / √ 24), which would give us the value of t. We then compare the calculated t value to the critical t value from the t-distribution table at n-1 degrees of freedom (in this case, 23) and a 1% significance level for a two-tailed test (since no direction is specified).

If the absolute value of the calculated t is greater than the critical t value, we reject the null hypothesis, otherwise, we fail to reject it.

User Jose Garrido
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories