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Determine the grams of ammonia produced when 1.15 g of hydrogen Hy is reacted with 3.75 g of nitrogen N2 to produce ammonia (NH3) according to the following chemical equation:

3H2 + N2 + 2NH3. (Type your numeric answer and submit).

1 Answer

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Final answer:

To determine the grams of ammonia produced when 1.15 g of hydrogen (H2) is reacted with 3.75 g of nitrogen (N2), use stoichiometry. Convert the grams of hydrogen and nitrogen to moles, use the mole ratio from the balanced equation, and then convert back to grams.

Step-by-step explanation:

To determine the grams of ammonia produced when 1.15 g of hydrogen (H2) is reacted with 3.75 g of nitrogen (N2), we need to use stoichiometry.

From the balanced chemical equation, we can see that 3 moles of hydrogen react with 1 mole of nitrogen to produce 2 moles of ammonia.

To calculate the grams of ammonia produced, we need to convert grams of hydrogen and nitrogen to moles, use the mole ratio from the balanced equation, and then convert back to grams.

Let's start by converting grams of hydrogen to moles:

1.15 g H2 * (1 mol H2 / molar mass of H2) = X moles H2

Next, let's convert grams of nitrogen to moles:

3.75 g N2 * (1 mol N2 / molar mass of N2) = Y moles N2

According to the mole ratio from the balanced equation, the moles of ammonia produced will be:

2 moles NH3 / 3 moles H2 = Z moles NH3

Finally, we can calculate the grams of ammonia produced:

Z moles NH3 * (molar mass of NH3 / 1 mol NH3) = grams of NH3

Plug in the values you calculated to find the final answer.

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