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In a bizarre but harmless accident, Superman fell from the top of the Eiffel Tower. How fast was Superman traveling right before he hit the ground 7.80 seconds later?

A) 7.80 m/s
B) 76.518 m/s
C) 9.81 m/s
D) 780 m/s
E) 0.78 m/s

User Izora
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1 Answer

3 votes

Final answer:

Superman's final velocity before hitting the ground is calculated using the kinematic equation for free fall, resulting in a final velocity of 76.518 m/s, which corresponds to option B.

Step-by-step explanation:

The question deals with the concept of free fall and the use of kinematic equations in physics. Specifically, it asks about the final velocity of Superman, who falls from the top of the Eiffel Tower and continues to accelerate downwards due to gravity for a duration of 7.80 seconds before hitting the ground.

To calculate the final velocity (v) before impact, we can use the kinematic equation v = gt, where g is the acceleration due to gravity (9.81 m/s²) and t is the time in seconds. Therefore, the final velocity of Superman right before hitting the ground after 7.80 seconds would be

v = 9.81 m/s² * 7.80 s = 76.518 m/s.

This matches option B) 76.518 m/s.

User Chris Bandy
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7.2k points