Question

What is the average kinetic energy molecule at 25 in degree celcius?

a) 1/2 kT
b) 2 kT
c) 3/2 kT
d) 4 kT

Answer 1

The average kinetic energy of a molecule at 25 degrees Celsius is given by the equation KE = (3/2)kT, corresponding to option c) 3/2 kT.

Step-by-step explanation:

The question is asking for the average kinetic energy of a molecule at 25 degrees Celsius. In physics, we know that the average kinetic energy (KE) of a molecule in an ideal monatomic gas is given by the equation KE = (3/2)kT, where k is the Boltzmann constant and T is the absolute temperature in Kelvin. To calculate this, we must convert the Celsius temperature to Kelvin by adding 273.15, making the temperature 298.15 K. So, the average kinetic energy of a molecule at 25 degrees Celsius is (3/2)kT, which corresponds to option c) 3/2 kT.