Final answer:
The ball will land 1.5 meters away from the starting point.
Step-by-step explanation:
In this problem, we can use the kinematic equations to solve for the distance the ball lands. The ball is initially launched horizontally with a speed of 5m/s and falls vertically due to gravity. We can use the equation:
d = v*t
where d is the distance, v is the horizontal velocity, and t is the time. The time can be found using the equation:
t = sqrt(2h/g)
where h is the height and g is the acceleration due to gravity. Plugging in the values, we get:
t = sqrt(2*0.9/9.8) = 0.3s
Now, we can substitute the values into the first equation to find the distance:
d = 5*0.3 = 1.5m
To solve for how far away the ball lands after rolling off a surface at a height of 0.9 meters above the ground, we must use the kinematics equations for projectile motion. The horizontal distance the ball travels can be found using the time it takes to fall vertically from the height of 0.9 meters and the horizontal velocity of the ball.