Final answer:
Chad walks along the road following y = 4x from his starting point (0,0) until he reaches point A (119,476), where he turns right and travels perpendicular to the original road, stopping at (119,0).
Step-by-step explanation:
Chad starts his walk at point (0,0) and moves along a road modeled by the equation y = 4x. This means he is walking in a straight line at a constant slope, moving northeast if we consider the positive direction of the x-axis as east and the positive direction of the y-axis as north. When Chad reaches a certain point A, he makes a right turn, which would be a perpendicular movement to his initial path. Traveling perpendicularly from a line with a slope of 4 implies that he should be moving along a horizontal line since the original path had a vertical rise for every unit of horizontal movement. Chad stops at the point (119,0), which is on the x-axis. Because he turned perpendicularly from the road y = 4x and ended up back on the x-axis, we know that point A, the point at which he turned, must have been directly above (119,0) on the line y = 4x. By plugging x = 119 into the equation of the road, we find the y-coordinate of point A is y = 4(119), which equals 476. Therefore, the exact location where Chad turned is point A(119, 476).