Final answer:
The solubility of CaCl₂ in water at 15°C is approximately 30 grams for 50 grams of water, based on the solubility at 0°C being 60 g per 100 g of water. However, none of the provided options match this calculation, hence without specific data at 15°C, an accurate choice cannot be made.
Step-by-step explanation:
The question is regarding the solubility of CaCl₂ in water at 15°C. While the provided reference doesn't give a direct answer to this, it does indicate that the solubility at 0°C is approximately 60 g per 100 g of water. To derive at the answer, we can generally expect that solubility increases with temperature, so at 15°C it would be reasonable to expect the solubility to be slightly higher than 60 g per 100 g of water. However, without specific solubility data at 15°C, we cannot answer with absolute certainty.
Based on this, if we assume the solubility doesn't significantly change, we can extrapolate that for 50 grams of water, the amount of CaCl₂ that would dissolve would be roughly half of the solubility in 100 grams of water at 0°C. Therefore, the closest answer based on the data would be about 30 grams, which is not an option here. Hence, we do not have enough information to accurately choose between the options, but we can eliminate options (a) and (d) as they would exceed the expected solubility at 0°C.