93.0k views
0 votes
Find the equation of the line perpendicular to y=3/4x+2 that runs through the point (3,-2) in slope-intercept form.

1 Answer

4 votes

Final answer:

To find the equation of a line perpendicular to y=3/4x+2 that runs through the point (3,-2) in slope-intercept form, we need to determine the slope of the new line. The slope of a line perpendicular to another line is the negative reciprocal of the slope of the original line.

Step-by-step explanation:

To find the equation of a line perpendicular to y=3/4x+2 that runs through the point (3,-2) in slope-intercept form, we need to determine the slope of the new line. The slope of a line perpendicular to another line is the negative reciprocal of the slope of the original line.

The original line has a slope of 3/4, so the perpendicular line will have a slope of -4/3.

Using the point-slope form of a line, we can substitute the slope and the given point into the equation y-y1=m(x-x1) to find the equation of the perpendicular line. Substituting (x1,y1)=(3,-2) and m=-4/3, we get the equation y-(-2)=(-4/3)(x-3).

Simplifying, we get the equation y+2=(-4/3)x+4. By rearranging the equation to slope-intercept form, we obtain the equation of the line perpendicular to y=3/4x+2 as y=(-4/3)x+2.

User Erick Stone
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories