Question

If a mystery rock has a density of 300 g/mL and is assumed to be homogeneous, what would be the mass of a perfect 1 cm³ cube cut out of this rock?

A) 300 g
B) 3 g
C) 0.03 g
D) 0.003 g

Answer 1

The mass of a perfect 1 cm³ cube cut out of a mystery rock with a density of 300 g/mL is 300 grams, using the formula mass = density x volume.

Step-by-step explanation:

If a mystery rock has a density of 300 g/mL, which is equivalent to 300 g/cm³ because 1 mL is the same volume as 1 cm³, and is assumed to be homogeneous, we can calculate the mass of a perfect cube of this rock that has a volume of 1 cm³. The mass of the rock can be calculated using the formula: mass = density × volume

Given the density (300 g/cm³) and the volume (1 cm³), we multiply these two values to find the mass:

mass = 300 g/cm³ × 1 cm³ = 300 g

Therefore, the mass of a perfect 1 cm³ cube cut out of this rock would be 300 grams (A) 300 g.