Question

A child slides down a hill on a toboggan with an acceleration of 2.8 m/s. If she starts with an initial push of 1.2 m/s, how far does she travel in 4.0s? ​

Answer 1

The child travels a distance of 22.4 meters in 4.0 seconds.

Step-by-step explanation:

To find the distance traveled by the child, we can use the equation:

d = v0t + (1/2)at2

where d is the distance, v0 is the initial velocity, t is the time, and a is the acceleration.

Substituting the given values into the equation, we have:

d = (1.2)(4.0) + (1/2)(2.8)(4.0)2 = 22.4 m

Therefore, the child travels a distance of 22.4 meters in 4.0 seconds.