Question

A block accelerates down a ramp at 0.5 meters/second squared. The initial velocity of the block is 3 meters/second, and it takes the block 10 seconds to reach the bottom. What is the block's velocity at the bottom of the ramp?

A) 2.0 meters/second
B) 4.0 meters/second
C) 6.0 meters/second
D) 8.0 meters/second

Answer 1

The block's velocity at the bottom of the ramp is calculated using the kinematic equation V = U + at and given values. The final velocity is found to be 8.0 meters/second.

Step-by-step explanation:

We can use the kinematic equation V = U + at, where V is the final velocity, U is the initial velocity, a is the acceleration, and t is the time. Given: Initial velocity (U) = 3 meters/second, Acceleration (a) = 0.5 meters/second squared, Time (t) = 10 seconds. Using the equation: V = U + at, V = 3 m/s + (0.5 m/s2)(10 s), V = 3 m/s + 5 m/s, V = 8 meters/second. Therefore, the block's velocity at the bottom of the ramp is 8.0 meters/second (Option D).