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How much time does it take for a car to come to rest if it has an initial speed of 22 m/s and slows with an acceleration of -6.1 m/s^2?

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Final answer:

It takes approximately 3.61 seconds for a car with an initial speed of 22 m/s to come to rest if it decelerates at a rate of -6.1 m/s².

Step-by-step explanation:

To determine how much time it takes for a car to come to rest if it has an initial speed of 22 m/s and an acceleration of -6.1 m/s², we use the kinematic equation that relates initial velocity, acceleration, and time. The equation we'll use is:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the car is coming to rest, the final velocity v will be 0 m/s. Rearranging the equation to solve for t gives us:

t = (v - u) / a

Plugging in the values:

t = (0 m/s - 22 m/s) / (-6.1 m/s²)

t = -22 m/s / -6.1 m/s² = 3.61 seconds (rounded to two decimal places)

Therefore, it takes approximately 3.61 seconds for the car to come to rest.

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