Question

Solution N is prepared by adding a certain amount of solute to a certain volume of solution Solution L is prepared by adding double the amount of the solute to double the

volume of solution. How does the molarity of Solution N compare to the molarity of Solution L ?
a) Solution N has two times higher molarity than Solution L
B) Solution N has one fourth the molarity of Solution L
C) They have the same molarity
D) Solution N has four times higher molarity than Solution L
E) Solution N has half the molarity of Solution L

Answer 1

The molarity of Solution N and Solution L is the same because doubling both the amount of solute and the volume maintains the same ratio of moles of solute to volume of solution.

Step-by-step explanation:

To compare the molarity of Solution N to Solution L, we can use the definition of molarity, which is the moles of solute divided by the liters of solution. If Solution N has a certain amount of solute added to a certain volume, and Solution L has double the amount of solute added to double the volume, the molarity for both solutions can be expressed as:

Molarity (M) = moles of solute / volume of solution (L)

Since Solution L has double both the moles of solute and the volume, the ratio that defines molarity remains the same:

M1 = moles1 / volume1
M2 = (2 × moles1) / (2 × volume1)

Therefore, after simplifying the equation for Solution L, the molarity M2 remains equal to M1. So the correct answer is:

C) They have the same molarity.